# How to Calculate Changes in Gene and Genotypic Frequencies Caused by Selection, Part 1

This post revisits several concepts discussed in the Population Genetics category. I’ve linked to the relevant pages as they come up below if you need a refresher.

Assume a locus A with alleles A_{1} and A_{2}. Either could be, but is not necessarily, dominant or recessive to the other.

*p* is the gene frequency of the A_{1} allele and *q* is the gene frequency of the A_{2} allele. (Similarly, *p* and *q* as used here do not necessarily ascribe dominance or recessiveness to either allele.)

*P* is the genotypic frequency of the A_{1}A_{1} genotype. *H* is the genotypic frequency of the A_{1}A_{2} genotype.*Q* is the genotypic frequency of the A_{2}A_{2} genotype.

Remember that *P* +* H* + *Q* = 1. If there are three genotypes in a population, the proportion of each as a percentage (its frequency) must add up to 100%, or 1.

We can express the proportions of *P*, *H* and *Q* as:

Assume these frequencies occur in a population from which parents have not yet been selected to produce the next generation.

If *their* parents were randomly mated, then this population should be in a Hardy-Weinberg equilibrium, thus:

*P* = *p*^{2}*H* = *2pq**Q* = *q*^{2}

Substituting these values into the formulae above, we get:

But we need to take into account the degree of dominance with respect to fitness for each of the genotypes A_{1}A_{1}, A_{1}A_{2} and A_{2}A_{2}.

Let *s*_{1} be the relative fitness *difference* for A_{1}A_{1}.

Let *s*_{2} be the relative fitness *difference* for A_{1}A_{2}.

Let *s*_{3} be the relative fitness *difference* for A_{2}A_{2}.

If A_{1}A_{1} is the fittest genotype (produces the most offspring), then its fitness difference, relative to itself, is *s*_{1} = 0, and its relative fitness is (1 - *s*_{1}) = (1 - 0) = 1.

If, hypothetically, the A_{1}A_{2} genotype produces 25% fewer offspring than the A_{1}A_{1} genotype, then the fitness difference, relative to the fittest genotype A_{1}A_{1}, is *s*_{2} = 0.25, and the relative fitness is (1 - *s*_{2}) = (1 - 0.25) = 0.75. We can say that the A_{1}A_{2} genotype is 75%, or 0.75 as fit as the A_{1}A_{1} genotype.

More generally, we can say that:

the relative fitness *value* for A_{1}A_{1} is (1 - *s*_{1}),

the relative fitness *value* for A_{1}A_{2} is (1 - *s*_{2}), and

the relative fitness *value* for A_{2}A_{2} is (1 - *s*_{3}).

In other words:

the relative *fitness* of A_{1}A_{1} is (1 - *s*_{1}) of its genotypic frequency *P*, or

(1 - *s*_{1}) × *P = *(1 - *s*_{1}) × *p*^{2}* = *(1 - *s*_{1}) *p*^{2}

Similarly, we can state the relative fitness of A_{1}A_{2} as (1 - *s*_{2})2*pq*, and the relative fitness of A_{2}A_{2} as (1 - *s*_{3})*q*^{2}.

We wish to select animals from this population to be the parents of the next generation. From this, their progeny become the next parents, with genotypic frequencies of *P*_{1}, *H*_{1} and *Q*_{1}. Can you see how the following formulae are the same as above, but this time we have taken into consideration the relative fitness values for each of *P*_{1}, *H*_{1} and *Q*_{1}:

In The Effect of Mating Systems on Gene and Genotypic Frequencies: Outbreeding, we saw how the gene frequency *q* = *Q* + ½*H*.

From this, the frequency of the A_{2} allele after selection is:

Substituting for *Q*_{1} and *H*_{1}, we get:

[Here we have ’simply’ added two (elaborate) fractions with a common denominator. This is just ^{a}/_{c} + ^{b}/_{c} = ^{a + b}/_{c} on steroids!]

As there are just two alleles A_{1} and A_{2}, with the respective gene frequencies *p* and *q *, these must add up to one, as *p* + *q* = 1. We can rewrite this as *p* = 1 - *q*.

We can substitute (1 - *q*) for p, cancel some terms, and rearrange the rest to get:

We now have a formula with which we can calculate the new gene frequency in the next population, given the initial gene frequency, the degree of dominance (if any), and the difference in fitness values (if any) of the various genotypes.

Next week we’ll run through some scenarios to see this in practice!

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